Question

∆PQR such that PQ = QR = PR = 5 cm.​

Answer 1

Answer:

PQR = 90°, and ∠P = ∠R

(opposite sides are equal)

∴∠P + ∠R = 90°

Hence ZP = ZR = \frac { 99\circ }{ 2 } = 45°

Steps of Construction:

Answer 2

Answer:

so it is an equilateral triangle

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