∆PQR~∆XYZ, PQ=12cm, QR=10cm, XY=30cm. if the perimeter of ∆PQR=40cm then find perimeter of ∆XYZ
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Given: triangle ABC ∼ triangle PQR, perimeter of triangle ABC = 32cm, perimeter of triangle PQR = 48cm and PR = 6cm
since the y are similar,
AB/PQ = BC/QR = AC/PR
AC/PR = perimeter of triangle ABC/perimeter of triangle PQR
AC/6 = 32/48
AC*48 = 6*32
therefore AC = 4cm
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