Question

∆ pqr ~ ∆ xyz pq = 6 cm qr = 8cm pr = 7cm xy =12cm find yz and xZ​

Answer 1

Answer:

yz 16, xz=14

Step-by-step explanation:

in similar triangles the ratios of the corresponding sides are equal so 6/12=1/2

now, 1/2=8/x, x=16cm, 1/2=7/y=14cm (yz=x, xz=y)

Answer 2

if triangle PQR~ triangle XYZ

then

$\frac{pq}{xy} = \frac{qr}{yz} = \frac{pr}{xz}$