∆PQR~∆XYZ, QR/YZ=3/5 then PQR=/ZYX=
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Answered by
0
Answer:
A(pQR)/A(XYZ)=QR^2/yz^2:: 3^2/5^2:: A(PQR)/A(XYZ)= 9:25. by theorem similarities of two triangles
Answered by
0
Answer:
answer is 9 and 25
ar(PQR)=9
ar(XYZ)=25
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