Question

∆PQRBL ~ ∆LMN , If QR = 15cm and MN = 10cm then ar(∆PQR)/ar(LMN) =​

Answer 1

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Side of triangle PQR = QR = 15 cm

Side of triangle of LMN = MN = 10 cm

BY Theorem :- the ratio of the area of two similar triangles is equal to the ratio of the square of the corresponding sides of similar triangles .

$\dfrac{\text{Area of triangle PQR}}{\text{Area of triangle LMN}}=\dfrac{QR^2}{MN^2} \\ \implies\dfrac{15^2}{10^2}\\ \implies \dfrac{9}{4}$

$\sf\dfrac{ar(∆PQR)}{ar(∆LMN)} =\dfrac{9}{4}$