Question

Pqrs is a convex quadrilateral prove that PQ + QR + Rs greater than PS

Answer 1

Answer:

Let PQRS be a convex quadrilateral as shown in the figure. QS is joined

We know that

In a triangle, the sum of two sides is always greater than the third side

Therefore,

In ΔPQS

PQ + QS > PS         ............ (1)

Again in ΔQRS

QR + RS > QS         ...............(2)

Adding both the inequalities

PQ + QS + QR + RS > PS + QR

or, PQ + QR + RS > PS                   (Hence Proved)

Answer 2

Answer:

the answer is root below in the attachment and is based on the principle that the sum of any two sides of the triangle is greater than the third side