PQRS is a cyclic quadrilateral. If the area of the shaded part is 72/7 sq units then find the radius of the circle
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R.E.F. Image.
Area of should part.
A=πr
2
−a
2
=
7
72
sq. unit
Putting the value of a
πr
2
−(
2
2r
)
2
=
7
72
7
22
.r
2
−
2
4r
2
=
7
72
7
22r
2
−14r
2
=
7
72
8r
2
=72
r
2
=9
r = 3 unit
Circle Area =πr
2
square Area =a
2
d = 2r
a=
2
d
a=
2
2r
[Δ QRS. d
2
=a
2
+a
2
(2r)
2
=2a
2
a=
2
2r
]
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