PQRS is a cyclic quadrilateral in which side PS and QR are produced to point T outside the circle.If PQ=RT and arc.PS=arc.RS prove that:
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In △TPS and △TRQ
∠PST=∠RQT
∠SPQ=∠QRT
[∵ exterior angle of cyclic quadrilateral is equal to the interior opposite angle]
∠T=∠T (common)
∴△TPS−△TRQ (By AA)
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