pqrs is a cyclic quadrilateral such that side PQ is the diameter of the circle point P are is equal to 115 the value of angle QPR is
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Please mark as brilliant please mark as brilliant
Step-by-step explanation:
PQRS is a cyclic quadrilateral.
Then, ∠PQR+∠PSR=180∘ ...[Opposite angles of cyclic quadrilateral are supplementary]
⟹ ∠PQR+150o=180∘
⟹ ∠PQR=180∘−150∘=30∘.
In △PQR,
∠PRQ=90∘ (Angle of a semicircle)
Then, ∠RPQ+90∘+30∘=180∘ ...[Angle sum property]
⇒∠RPQ+120∘=180∘
⇒∠RPQ=60∘.
Hence, option B is correct.
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