Pqrs is a cyclic quadrilateral the diagonals pr and qs intersect at o. prove that pq+ps+r+ qr< 2(pr+ps)
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27(7)^1/2
perimeter = 2l + b
l is length of each of the equal sides and b is length of base.
solving, 2l+3/2l=42,
l=12
b=18
the altitude divides the base into 2 equal parts,
so applying Pythagoras theorem, altitude= (63)^1/2
area = 1/2(altitude)(base)= 27((7)^1/2)
perimeter = 2l + b
l is length of each of the equal sides and b is length of base.
solving, 2l+3/2l=42,
l=12
b=18
the altitude divides the base into 2 equal parts,
so applying Pythagoras theorem, altitude= (63)^1/2
area = 1/2(altitude)(base)= 27((7)^1/2)
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