PQRS is a //gm Amd X and Y trisect sides OR. Show that ar( triangle PQS) =ar( triangleSRY).
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here, it is given :- PQRS is a parallelogram ,
So we know PQ = RS and PQ | | RS and QR = SP and QR | | SP
And
X and Y trisect the side QR , So
QX = XY = RY --------------------【 1 】
We know , Area of triangle = 1/2×Base×Height
And Height of both triangle PQX and SRY is = h , As ( These triangle are lies between same parallel lines QR | | SP )
SO,
Area of ∆ PQX = 12QX × h......................【 2 】
And
Area of ∆ SRY = 12RY × h ,
Substitute values from equation 1 and get
Area of ∆ SRY = 12QX × h.....................【 3 】
From equation【 2】 and【 3 】, we get
Area of PQX = Area of SRY ( Hence proved )...............................【 ANS】
here, it is given :- PQRS is a parallelogram ,
So we know PQ = RS and PQ | | RS and QR = SP and QR | | SP
And
X and Y trisect the side QR , So
QX = XY = RY --------------------【 1 】
We know , Area of triangle = 1/2×Base×Height
And Height of both triangle PQX and SRY is = h , As ( These triangle are lies between same parallel lines QR | | SP )
SO,
Area of ∆ PQX = 12QX × h......................【 2 】
And
Area of ∆ SRY = 12RY × h ,
Substitute values from equation 1 and get
Area of ∆ SRY = 12QX × h.....................【 3 】
From equation【 2】 and【 3 】, we get
Area of PQX = Area of SRY ( Hence proved )...............................【 ANS】
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