pqrs is a pallogram. se perpendicular to pq, qf perpendicular to PS if sr=13cm ps=6.5cm,se=6cm find qf
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pqrs ia a parallelogram
SR =PQ=13cm
PS=RQ=6.5cm
triangle SfP ia a right angled triangle
SP^2 =SF^2 + PF^2
6.5^2 =6^2 +PF^2
PF^2 = 42.25 -36
PF = 2.5cm
PQ=PF+FQ
FQ=PQ - PF
= 13 -2.5
FQ= 10.5
Hope this helps...
SR =PQ=13cm
PS=RQ=6.5cm
triangle SfP ia a right angled triangle
SP^2 =SF^2 + PF^2
6.5^2 =6^2 +PF^2
PF^2 = 42.25 -36
PF = 2.5cm
PQ=PF+FQ
FQ=PQ - PF
= 13 -2.5
FQ= 10.5
Hope this helps...
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