Pqrs is a parallelelogram, PO &qo are the bisector of angle p&angle q respectively. Prove that poq=90
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Given:
1. PQRS is a parallelogram where the opposite sides are parallel and equal .
2. PO & QO are the angle bisector of angle P and Q respectively.
To prove that:
Angle POQ is 90°
Step-by-step explanation:
Proof:
In parallelogram PQRS
Angle P + angle Q = 180°
(Co-interior angle)
1/2 angle P + 1/2 angle Q = 180°/2 = 90°
From 2 we get:
Angle OPQ + angle OQP = 90°.................(i)
In triangle OPQ,
Angle (OPQ + OQP + POQ) = 180°.............(ii)
(Angle sum property)
From (i)and(ii) , we get:
Angle POQ = 180° - Angle( OPQ + OQP)
= 180° - 90° = 90°
Hence Proved.
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