PQRS. Is a parallelogram and the bisector of angle p bisects QR at m.show PS=2pq
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Step-by-step explanation:
Given:
Here PQRS is a parallelogram and PM bisects QR
So, QM = MR (1)
also, PM bisects angle P
∠ SPM = ∠ MPQ (2)
Now, PS || QR and PM is transversal
so, ∠ SPM = ∠ PMQ (alternate interior angles) (3)
from (2) and (3)
∠ MPQ = ∠ PMQ
so, QM = PQ (sides opposite to equal angles are equal in a triangle) (4)
From (1) and (4)
PQ = QM = MR
Now, QM + MR = QR
QR = PQ + PQ ( since PQ = QM = MR)
or, QR = 2(PQ)
Also, QR = PS (Opposite sides of a parallelogram are equal)
So, PS = 2 PQ
Hence proved.
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