pqrs is a parallelogram E is a point on pq such that qe=2pe and f is a point on rs such that 2rf=sf show that perf is a parallelogram and perf =1/3pqrs
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since qe=2pe and sf=2rf.so pe=fr.
and since pe parallel fr.
or, perf is a parallelogram. and pq=3pe similarly, sr=3fr.
thus parallelogram perf and pqrs lie in the same line( their sides).so their height must be equal. and pe=1/3pq ,fr=1/3sr.
then ar ( perf)=1/3ar(pqrs)
and since pe parallel fr.
or, perf is a parallelogram. and pq=3pe similarly, sr=3fr.
thus parallelogram perf and pqrs lie in the same line( their sides).so their height must be equal. and pe=1/3pq ,fr=1/3sr.
then ar ( perf)=1/3ar(pqrs)
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