PQRS is a parallelogram if diagonals are equal. Find the value of angle SPQ.
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Therefore, the incorrect statement is AQ=PQ.
We have ∠SPQ=60 degree
∠P+∠Q=180 (adj. ∠s of a || gm are supp)
∠Q=180 degree - 60 degree = 120 degree
Now PQ∣∣SR and AP is the transversal.
∴SAP=∠APQ=30∘ (∵AP bisects ∠SPQ)
∠SPA=∠SAP⇒SA=SP (isos. Δ property) ...(i)
Also ∠RAQ=∠AQP=60 degree
(PQ∣∣SR,AQ is transversal, alt ∠s)
and ∠AQP= 1/2 ∠PQR=60 degree
⇒∠RQA=∠RAQ (AQ bisect ∠PQR)
⇒RA=RQ (isos. Δ property) ....(ii)
∴ from eqn. (i) and (ii)
AS=AR (∵SP=RQ, opp. side of a ||gm)
Also, in ΔARQ,∠ARQ=60 degree
⇒ΔARQ is equilateral
⇒AR=RQ⇒AR=SP
Therefore, the incorrect statement is AQ=PQ.
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