Question

PQRS is a parallelogram in which ∠SPQ = 80°.

Bisector of ∠P and ∠Q meet SR at A. Prove that:

(i) PS = SA (ii) RA = RQ (iii) SR = 2 PS​

Answer 1

Answer:

PQRS is a parallelogram in which ∠SPQ = 80°.

Bisector of ∠P and ∠Q meet SR at A. Prove that:

(i) PS = SA (ii) RA = RQ (iii) SR = 2 PS