PQRS is a parallelogram in which X is the mid point of PQ ans SX bisects angle PSR prove that RX bisects angle SRQ also
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ang. psx=ang. xsr.....(1)
ang. pxs=ang .xsr ......(2)
from 1 and 2,
ang.PSX=angPXS.
PX=XQ
PS=QR
therefore ang .psx=pxs=qsr=qrs
ang qxr=ang xrs.......(3)
ang qxr=qrs..........(4)
from,(3) and(4) ,
ang srx=qrx
therefore,XR bisects ang qrs.
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ang. pxs=ang .xsr ......(2)
from 1 and 2,
ang.PSX=angPXS.
PX=XQ
PS=QR
therefore ang .psx=pxs=qsr=qrs
ang qxr=ang xrs.......(3)
ang qxr=qrs..........(4)
from,(3) and(4) ,
ang srx=qrx
therefore,XR bisects ang qrs.
pls mark me brainliest.
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