PQRS is a parallelogram. Measurements of its sides are given below (in cm):
PQ = 2x + 2 , QR = y - 2 , RS = 8 , PS = 7
Find the values of x and y.
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here is yr answer
opposite side of parallelogram are equal
PQ=SR
2x+2=8
2x=6
x=3
PS=QR
y-2=7
y=9
x=3 and y=9
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PQRS is a parallelogram.
PQ∥SR and SQ is a transversal.
∴ ∠RSQ=∠PQS [ Alternate angles ]
⇒ 48
o
=4x
⇒ x=
4
48
o
⇒ x=12
o
SP∥RQ and SQ is transversal.
∴ ∠PSQ=∠RQS [ Alternate angles ]
⇒ 63
o
=7y
⇒ y=
7
63
o
⇒ y=9
o
∴ The values of x and y are 12
o
and 9
o
.
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