PQRS is a parallelogram with PQ = 26cm AND QR=20cm. if the distance between its longer sides is 12.5cm, find. (i) the area of the parallelogram; (ii) the distance between its shorter sides.
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161
given that,
In PQRS parallelogram,
PQ=26cm
QR=20cm
distance between longer sides =12.5cm
(i) Area of parallelogram=base ×height cm^2
=PQ×h
=26×12.5
=325 cm^2
(ii)Area of parallelogram=base×height
height=Area/base
distance b/wshorterside=325/20
=65/4
=16.25cm
In PQRS parallelogram,
PQ=26cm
QR=20cm
distance between longer sides =12.5cm
(i) Area of parallelogram=base ×height cm^2
=PQ×h
=26×12.5
=325 cm^2
(ii)Area of parallelogram=base×height
height=Area/base
distance b/wshorterside=325/20
=65/4
=16.25cm
Answered by
16
Answer:
Step-by-step explanation:
given that,
In PQRS parallelogram,
PQ=26cm
QR=20cm
distance between longer sides =12.5cm
(i) Area of parallelogram=base ×height cm^2
=PQ×h
=26×12.5
=325 cm^2
(ii)Area of parallelogram=base×height
height=Area/base
distance b/wshorterside=325/20
=65/4
=16.25cm
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