PQRS is a quadrilateral
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we know that sum of two sides of triangle is greater than third
so
in PQR
PQ+RQ >PR. (1)
IN RQS
RS+RQ>SQ
RQ = SP (opposite side of parallelogram)
so
RS+SP>SQ. (2)
adding equation (1) and(2)
PQ+QR+RS+SP>PR+QS
hence proved
so
in PQR
PQ+RQ >PR. (1)
IN RQS
RS+RQ>SQ
RQ = SP (opposite side of parallelogram)
so
RS+SP>SQ. (2)
adding equation (1) and(2)
PQ+QR+RS+SP>PR+QS
hence proved
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