Question

PQRS is a quadrilateral. Find angle Q, angle R, and angle S if Q is (5x-10) R is (3x-10) S is (2x-10)
pls

Answer 1

Answer:

HERE IS THE ANSWER:

Q= 100°

R=56°

S=34°

Answer 2

Answer:

∠Q = 55°

∠R = 125°

∠S = 55°

Note:

It would be possible to do this, only if it's a parallelogram. Though it is not mentioned, I would assume that the given quadrilateral is a parallelogram and am solving accordingly.

Step-by-step explanation:

We know that, opposite angles of a parallelogram are equal.  

∴ ∠Q=∠S  

⇒ 4x−5=3x+10  

⇒ 4x−3x=10+5  

⇒ x=15°  

⇒ ∠Q=∠S(4x−5)

⇒ (4×15−5)°  = 55°

We know that, sum of adjacent angles of parallelogram is 180 °

⇒ ∠Q+∠R=180°

⇒ 55° + ∠R = 180°

⇒ ∠R = 125°