pqrs is a quadrilateral in which PS equal to Q R and angle qps equal to angle pqr prove that (i) triangle pqs congruent to triangle QPR (ii) p r = qs (iii) angle QPR equals to angle ppqs
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Answers
Given:
PQRS is a quadrilateral
PS = PQ
∠QPS = ∠PQR
To find:
Prove that
(i) Δ PQS is congruent to Δ QPR
(ii) PR = QS
(iii) ∠QPR equals to ∠PQS
Solution:
(i) Proving triangle PQS is congruent to triangle QPR:
In Δ PQS and Δ QPR, we have
PS = QR ...... (given)
∠QPS = ∠PQR ..... (given)
PQ = PQ ...... (common side to both the triangles)
∴ Δ PQS ≅ Δ QPR ...... By SAS Congruency
Hence proved
(ii) Proving PR = QS:
We know that → when two triangles are congruent to each other then their corresponding sides are equal in length.
Here
Δ PQS ≅ Δ QPR
and
PR & QS are the corresponding sides of the two congruent triangles
∴ PR = QS
Hence proved
(iii) Proving ∠QPR = ∠PQS:
We know that → when two triangles are congruent to each other then their corresponding angles will have the same measurement.
Here
Δ PQS ≅ Δ QPR
and
∠QPR & ∠PQS are the corresponding angles of the two congruent triangles
∴ ∠QPR = ∠PQS
Hence proved
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