Math, asked by ghoshsrija95, 9 months ago

pqrs is a quadrilateral in which PS equal to Q R and angle qps equal to angle pqr prove that (i) triangle pqs congruent to triangle QPR (ii) p r = qs (iii) angle QPR equals to angle ppqs


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Answers

Answered by bhagyashreechowdhury
3

Given:

PQRS is a quadrilateral

PS = PQ

∠QPS = ∠PQR

To find:

Prove that

(i) Δ PQS is congruent to Δ QPR

(ii) PR = QS

(iii) ∠QPR equals to ∠PQS

Solution:

(i) Proving triangle PQS is congruent to triangle QPR:

In Δ PQS and Δ QPR, we have

PS = QR ...... (given)

∠QPS = ∠PQR ..... (given)

PQ = PQ ...... (common side to both the triangles)

Δ PQS ≅ Δ QPR ...... By SAS Congruency

Hence proved

(ii) Proving PR = QS:

We know that → when two triangles are congruent to each other then their corresponding sides are equal in length.

Here

Δ PQS ≅ Δ QPR

and

PR & QS are the corresponding sides of the two congruent triangles

PR = QS

Hence proved

(iii) Proving ∠QPR = ∠PQS:

We know that → when two triangles are congruent to each other then their corresponding angles will have the same measurement.

Here

Δ PQS ≅ Δ QPR

and

∠QPR & ∠PQS are the corresponding angles of the two congruent triangles

∠QPR = ∠PQS

Hence proved

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Answered by parnabhowmick1978
3

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