PQRS is a quadrilateral. Prove that PQ + QS + RS + RP > PS+ QR.
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Step-by-step explanation:
Given:
Quadrilateral PQRS circumscribes a circle
To prove that:
PQ+RS=PS+QR
Proof:
Lengths of tangents drawn to a circle from an external point are equal.
Hence, PA=PD(i)
QA=QB(ii)
RB=RCiii)
SC=SD(iv)
LHS
PQ+RS=PA+AQ+RC+CS(v)
RHS
PS+QR=PD+DS+QB+BRvi)
=PA+CS+AQ+RC using equations (i), (ii), (iii) and (iv)
From above, it can be seen LHS = RHS
Hence proved
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