Question

PQRS is a quadrilateral with angle q=65 ° and angle S=105° . IF angle P and angle R are in the ratio 3:7 , find angle P and angle R​

Answer 1

let P=3x

R = 7 x

Given S = 105 , Q = 65

ATQ

P+Q+R+S= 360 ( ANGLES OF ANY QUADRILATERAL ADD UPTO 360⁰)

Therefore,

3x + 105+ 7x +65= 360

10x + 170= 360

10x =360- 170

10 x = 190

x = 190/10

x = 19

Now P = 3x = 3 (19)= 57⁰

R = 7x = 7 (19)= 133⁰