PQRS is a quadrilateral with <Q
= 65° and <S = 105°. If <P and < R
are in
the ratio 3:7, find <P and <R
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Given : PQRS is a quadrilateral with Q = 65° and S = 105°
∠P and ∠R are in ratio 3 : 7
To Find : ∠P and ∠R
Solution:
∠P and ∠R are in ratio 3 : 7
∠P = 3A
∠R = 7A
∠P + ∠Q + ∠R + ∠S = 360° ( sum of angles of a Quadrilateral )
=> 3A + 65° + 7A + 105° = 360°
=> 10A = 190°
=> A = 19
∠P = 3A = 3 x 19 = 57°
∠R = 7A = 7 x 19 = 133°
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