PQRS is a rectangle. Find the angles marked with “x” and “y”.
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QPR=PRS=24°
PRQ=Y=90°-24°=66°
Since the diagonal of rectangle bisect each other •°• :--
OQP=OPQ=24°{angle opposite to equal sides are equal}
Now in triangle POQ
POQ+OQP+OPQ=180° {ANGLE SUM PROPERTY}
X+24°+24°=180°
X=180°-48°
X=132°
so x=132° and y=66°
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