PQRS is a rectangle in which PQ=20 QR=10. A semicircle is drawn with centre O with radius 10root 2 cm. it passes through A and B. find the shaded region.
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Area of rectangle ABCD=L*B=20*10=200cm2
Here, angle AOB=90 degree
OAEB is an sector of radius OA=OB=10root2
Area of sector=90/360*22/7*10root2*10root2
=1100/7=157.14cm2
Area of OAB=1/2*10root2*10root2
=100cm2
Area of shaded region=area of rectangle ABCD-(area of sector OAEB-area of OAB)
=200-(157.14-100)
=200-57.14
=142.86cm2
Hence area of shaded region =142.86cm2
Hope it helps
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Here, angle AOB=90 degree
OAEB is an sector of radius OA=OB=10root2
Area of sector=90/360*22/7*10root2*10root2
=1100/7=157.14cm2
Area of OAB=1/2*10root2*10root2
=100cm2
Area of shaded region=area of rectangle ABCD-(area of sector OAEB-area of OAB)
=200-(157.14-100)
=200-57.14
=142.86cm2
Hence area of shaded region =142.86cm2
Hope it helps
do Mark it as brainliest
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