Math, asked by biggyboo7008, 11 months ago

PQRS is a rectangle inscribed in a quadrant of a circle of radius 13 cm. A is any point on PQ. If PS = 5 cm, then find ar(ΔRAS)

Answers

Answered by Anonymous
3

Heyaa There!!!

Given Pqrs is a rectangle inscribed in a quadrant of a circle of radius 13 cm. A is any point on pq. If ps = 5 cm, then area (ras) is

qs = 13 cm (in a quadrant of circle radius is given as 13 cm)

From triangle qps

From pythogoras theorem we have,

qs^2 = ps^2 + pq^2

13^2 = 5^2 + pq^2

169 = 25 + pq^2

pq^2 = 144

pq = 12 cm

sr is also equal to 12 cm (because pq = sr)

Now area of triangle = 1/2 base x height

area of triangle asr = 1/2 x sr x ps

= 1/2 x 12 x 5

= 30 cm^2

Area of triangle ras = 30 cm^2

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