Pqrs is a rectangle inscribed in a quadrant of a circle of radius 13 cm. A is any point on pq. If ps = 5 cm, then ar(ras) is
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37
Answer:
30 cm^2
Step-by-step explanation:
Given Pqrs is a rectangle inscribed in a quadrant of a circle of radius 13 cm. A is any point on pq. If ps = 5 cm, then area (ras) is
qs = 13 cm (in a quadrant of circle radius is given as 13 cm)
From triangle qps
From pythogoras theorem we have,
qs^2 = ps^2 + pq^2
13^2 = 5^2 + pq^2
169 = 25 + pq^2
pq^2 = 144
pq = 12 cm
sr is also equal to 12 cm (because pq = sr)
Now area of triangle = 1/2 base x height
area of triangle asr = 1/2 x sr x ps
= 1/2 x 12 x 5
= 30 cm^2
Area of triangle ras = 30 cm^2
Answered by
2
Answer:True.30c.m^2
Step-by-step explanation: N/A
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