Question

PQRS is a Rhombas
Diagonals PR L QS
are intersects at m If I (Qm) = 6 cms ? t
(MR) = 8cm find the side of Rhombos?​

Answer 1

Answer:

We know that, sides of rhombus are equal.

So, PQ=QR=RS=PS=6cm

⇒ Draw a line segment PQ=6cm

⇒ Take P as center with radius 8cm and draw an arc.

⇒ Take Q as center with radius 6cm and draw an arc, which meets previous arc at point R.

⇒ Take P as center with radius 6cm and draw an arc.

⇒ Take R as center with radius 6cm and draw an arc, which meets previous arc at point S.

⇒ Join QR,RS,SP,PR and QS

∴ PQRS is a required rhombus.

⇒ Measure the length of QS.

We get QS=8.9cm

solution

Answer 2

Step-by-step explanation:

We know that, sides of rhombus are equal.

So, PQ=QR=RS=PS=6cm

⇒ Draw a line segment PQ=6cm

⇒ Take P as center with radius 8cm and draw an arc.

⇒ Take Q as center with radius 6cm and draw an arc, which meets previous arc at point R.

⇒ Take P as center with radius 6cm and draw an arc.

⇒ Take R as center with radius 6cm and draw an arc, which meets previous arc at point S.

⇒ Join QR,RS,SP,PR and QS

∴ PQRS is a required rhombus.

⇒ Measure the length of QS.

We get QS=8.9cm

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