PQRS is a rhombus and angle PQS =42°,Find angle PQR
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let both the diagonal of rhombus intersect at O
now ∆ PQO is congruent to ∆ RQO (RHS) or SAS property
so angle PQO is equal to angle RQO ..
so ANGLE RQO = 42
so angle PQR = 42+42= 84
PLS MARK AS BRAINLIEST
now ∆ PQO is congruent to ∆ RQO (RHS) or SAS property
so angle PQO is equal to angle RQO ..
so ANGLE RQO = 42
so angle PQR = 42+42= 84
PLS MARK AS BRAINLIEST
varun2003k:
pls mark as brainliest pls
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