pqrs is a rhombus diagonals pr and qs bisect each other at point o such that a is equal to 6 cm and qs is equal to 8 cm each side of rhombus is
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Answer:
area = 52 cm^2
Step-by-step explanation:
diagonals of rhombus biset each other at 90 degree.
so
apply Pythagoras theorem: h^2 = p^2 + b^2
by this you will find side = 13 cm
as h = \begin{gathered}\sqrt(12)^2 + (5)^2 \\\end{gathered}
(
12)
2
+(5)
2
= 13 cm
so perimeter = 4*13 = 52 cm^2
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