Math, asked by deepikakaura69, 2 months ago

• PQRS is a rhombus:
(i) If it is given that PQ = 3 cm, calculate the
perimeter of PQRS.
(ii) If the height of the rhombus is 2.5 cm,
calculate the area.
(iii) If the diagonals cut at 0, state the size of
the angle POQ in degrees.
(ICSE)​

Answers

Answered by varadbhoj
1

Answer 1 :

Measurement of Line PQ - 3 cm

All sides of a Rhombus are of equal measurement.

Hence, the perimeter of Rhombus PQRS

= 3 × 3 × 3 × 3

= 3 × 4

= 12 cm.

Answer 2 :

The height of Rhombus = 2.5 cm

So, it's width is also 2.5 cm

Area of a Rhombus

 =  \frac{d1 \times d2}{2}  \\  =  \frac{2.5 \times 2.5}{2}  \\  =  \frac{5}{2}  \\  = 2.5 \: cm

Answer 3 : Sorry, I don't know this one.

Answered by munazir14
3

Answer:

i) 12 cm;

ii)7.5 sq. cm

iii) 90°

Step-by-step explanation:

i) Perimeter of rhombus= 4 × side = 4 × PQ = 4 × 3 cm = 12 cm

ii) Area of rhombus = height × base ( here base is any side of rhombus) = (2.5 × 3) sq. cm = 7.5 sq. cm

iii) Since diagonals of a rhombus bisects perpendicularly. So, angle POQ = 90° .

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