PQRS is a rhombus. If angle PSQ = 50°, find the angles of the rhombus.
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hey mate here is your answer
Given: PQRS is a rhombus
PQS= 50*
to find - angle P,Q,R,S
i.e. PQS=PSQ(adjacent sides of a rhombus are equal)
in triangle PSQ
PSQ+PSQ+P=180*
2PSQ+P=180*
100+P=180*
P=80*
also ,P=R=80*
angle P+Q=180*(when two lines are parallel and cut by a transversal then angles formed are supplementary)
so angle Q= 180- P
Q=180-80=100*
also Q=S=100*
So , Angle P and R= 80*
and Q and S = 100*
mark me brainliest
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