PQRS is a rhombus If <PRQ= 25°, find <PSQ
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2
Answer:
Correct option is
B
∠PRS=63
∘
Given that PQRS is a rhombus
∠PSR=∠PQR=54
∘
(opp. ∠S of a rhombus are equal)
⇒∠OSR=
2
1
×∠PSR=
2
1
×54
∘
=27
∘
(SQ bisects ∠PSR)
Now in ΔOSR
∠ORS+∠ROS+∠OSR=180
∘
⇒∠ORS+27
∘
+90
∘
=180
∘
(Diagonals of a rhombus bisect each other at right ∠s)
⇒∠ORS=63
∘
⇒∠PRS=63
∘
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