Question

PQRS is a rhombus. If PQ=10cm and QR=x+2, then the value of ‘x’ is_​

Answer 1

Solution :-

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As we know , all sides of rhombus are equal

Therefore , 10 = x + 2

10 - 2 = x

x = 8

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Answer 2

Answer:

x = 8

Step-by-step explanation:

The four sides of rhombus are equal then,

PQ = 10

QR = 10

RS = 10

SP = 10

10+10+10+10 = 40

10+10=(x+2)+(x+2)

= 20=2x+4

= 20-4=2x

= 16=2x

= x=16/2

x=8