Question

PQRS is a rhombus , O is intersecting point of diagonals PR and QS and OP

=8cm , OS = 6cm . Then perimeter of PQRS is​

Answer 1

Answer:

PLEASE MARK BRAINLIEST!!

see , the rhombus is a quadrilateral that has all sides equal so if you find even one side then you can multiply it by 4 for perimeter .

now for that one side :

draw a figure of the quadrilateral and join its diagonals , also put the measures of OP and OS in figure

now comes the point, the diagonals in a rhombus bisect at 90 degree so in the question OP is perpendicular of a triangle in pqrs rhombus and OS is your base

use pythagoras to find PS which is (8)²×(6)²=(PS)²

                                                   ⇒64+36=(PS)²

                                               ⇒√100=PS

                                  therefore        ⇒PS=10cm which is your answer

                                                   

PLEASE DONT FORGET TO MARK ME AS BRAINLIEST!!