Pqrs is a rhombus of side 100cm and one of its diagonal is 160m .Find its area
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Hey mate, here's you answer
the diagonal of a rhombus are perpendicular and bisect each other
given length of side is 100 cm and one diagonal as 160 cm
from the given figure, Let AC= 160 cm
so, OC and OA = 80 cm
now consider triangle OCB as a right angled triangle
we know that OC=80cm and CB=100 cm
using pythagoras theorm
(100)^2=(80)^2+(OB)^2
(OB)^2= (100)^2 - (80)^2
(OB)^2=3600
OB = 60
So the length of diagonal DB= 2*60= 120 sq.cm
the diagonal of a rhombus are perpendicular and bisect each other
given length of side is 100 cm and one diagonal as 160 cm
from the given figure, Let AC= 160 cm
so, OC and OA = 80 cm
now consider triangle OCB as a right angled triangle
we know that OC=80cm and CB=100 cm
using pythagoras theorm
(100)^2=(80)^2+(OB)^2
(OB)^2= (100)^2 - (80)^2
(OB)^2=3600
OB = 60
So the length of diagonal DB= 2*60= 120 sq.cm
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