Question

PQRS is a rhombus. The diagonals PR and QS bisect each other
at a point O such that PR=24cm and QS=10cm. Find the
perimeter of the rhombus.

Answer 1

Answer:

area = 52 cm^2

Step-by-step explanation:

diagonals of rhombus biset each other at 90 degree.

so

apply Pythagoras theorem: h^2 = p^2 + b^2

by this you will find side = 13 cm

as h = $\sqrt(12)^2 + (5)^2$ = 13 cm

so perimeter = 4*13 = 52 cm^2

plz mark it as brilliant ans

Answer 2

Step-by-step explanation:

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