PQRS is a rhombus whose angle PQR = 60°,find angle RPS
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Given that PQRS is a rhombus
∠PSR=∠PQR=54∘ (opp. ∠S of a rhombus are equal)
⇒∠OSR=21×∠PSR=21×54∘=27∘ (SQ bisects ∠PSR)
Now in ΔOSR
∠ORS+∠ROS+∠OSR=180∘
⇒∠ORS+27∘+90∘=180∘
(Diagonals of a rhombus bisect each other at right ∠s)
⇒∠ORS=63∘
⇒∠PRS=63∘
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