Question

PQRS is a rhombus whose diagonals intersect at M. If PQ=10cm and one

diagonal QS=16cm. Find the length of the other diagonal PR.​

Answer 1

Answer:

Side of Rhombus are equal.

AB = BC = CD = DA

∴AC=

4×(side)

2

−(DiagonalBD)

2

AC=

4×(10)

2

−(16)

2

=

400−256

=

144

=12cm