Math, asked by srushpanjain8674, 11 months ago

Pqrs is a rhombus whose diagonals pr and qs intersect at o. If pq = 10 cm and diagonal qs = 16 cm , find the length of diaginal

Answers

Answered by ravikalashetty719
8

Answer:

It's very easy to understand

Step-by-step explanation:

In rhombus PQRS,

PQ=QR=RS=PS=10cm

...Diagonals of rhombus bisect each other perpendicularly, .... 1

therefore,

QO=half of QS

QO=half of 16QO

QO=8cm

In PQS,

PO becomes median, ...from1,

by Apollonius theorem,

PQSquare+PSSquare=2QOSquare+2POsquare

10×10+10×10=2×8×8+2POsquare

200-128=2POsquare

we get,

POsquare=72/2

PO=√36

PO=6cm

therefore,

from1, PQ=2of PO

PQ=2×6=12cm

Length of diagonal=12cm

So it's all based on concept

I hope it will be understandable for u Thanku

Answered by kranjeet488
14

Answer:

Step-by-step explanation:

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