Pqrs is a rhombus whose diagonals pr and qs intersect at o. If pq = 10 cm and diagonal qs = 16 cm , find the length of diaginal
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8
Answer:
It's very easy to understand
Step-by-step explanation:
In rhombus PQRS,
PQ=QR=RS=PS=10cm
...Diagonals of rhombus bisect each other perpendicularly, .... 1
therefore,
QO=half of QS
QO=half of 16QO
QO=8cm
In PQS,
PO becomes median, ...from1,
by Apollonius theorem,
PQSquare+PSSquare=2QOSquare+2POsquare
10×10+10×10=2×8×8+2POsquare
200-128=2POsquare
we get,
POsquare=72/2
PO=√36
PO=6cm
therefore,
from1, PQ=2of PO
PQ=2×6=12cm
Length of diagonal=12cm
So it's all based on concept
I hope it will be understandable for u Thanku
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