PQRS IS A RHOMBUS WITH ANGLE PQR =55* AND ANGLE PRS .
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Answered by
17
Given
∠PQR = 55⁰.
Therefore,
∠PQR + ∠QRS = 180⁰{ Sum of adjacent angles
is 180⁰}.
∠55⁰ + ∠QRS = 180⁰
Thus,
∠QRS = 180⁰- 55⁰= 125⁰.
Join P and Q to form a diagonal of PQRS rhombus.
Therefore,
∠PRS = ½ ∠QRS. { Diagonals of rhombus bisects the angles into two equal halves.
So, ∠PRS = ½ × 125⁰.
So, ∠PRS = 62 ½⁰. or 62.5⁰. ANS.
Hope this will help you. Marks this as brainlist.
∠PRS =
∠PQR = 55⁰.
Therefore,
∠PQR + ∠QRS = 180⁰{ Sum of adjacent angles
is 180⁰}.
∠55⁰ + ∠QRS = 180⁰
Thus,
∠QRS = 180⁰- 55⁰= 125⁰.
Join P and Q to form a diagonal of PQRS rhombus.
Therefore,
∠PRS = ½ ∠QRS. { Diagonals of rhombus bisects the angles into two equal halves.
So, ∠PRS = ½ × 125⁰.
So, ∠PRS = 62 ½⁰. or 62.5⁰. ANS.
Hope this will help you. Marks this as brainlist.
∠PRS =
Answered by
4
Answer:
62.5 degree
Step by step explanation:
Opposite angles of a rhombus are equal therefore angle PQR = angle PSR is equals to 55 degree
360 - 110 = 250degree
=> angle SPQ = angle SRQ = 125degree
diagonal of a Rhombus bisect the angle therefore angle PRS = 62.5 degree
Hope it helps you : )
Pls marks brainliest
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