PQRS is a rhombus with PQ = 10 cm if OQ = 6 CM then what is the length of the diagonal PR
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Answered by
28
Answer:
Step-by-step explanation:In triangle POQ ,PQ is 10 cm and OQ is 6cm
diagonals bisect perpendicular therefore by pythagoras theorem
(OQ)² + (PO)²=(PQ)²
(6)²+(PO)²=(10)²
(PO)²=100-36
(PO)²=64
∴(PO)=√64
∴(PO)=8
IN Rhombus diagonals bisect each other
∴PR=8×2
=16cm
Answered by
7
Answer:
PO=8cm
PR =2 X PO
=2X 8
=16 cm
Step-by-step explanation:
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