PQRS is a square E and F are the point on side QR and RS respectively. show that area triangle PQE is equal to area triangle PSF when it is given that QS is parallel to EF
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In square we know
PE=PF
PQ=PS
‹PSF = ‹PQE
∆PSF congruent to ∆PQE
then SF=QE
that's the process to show two triangles are equal
PE=PF
PQ=PS
‹PSF = ‹PQE
∆PSF congruent to ∆PQE
then SF=QE
that's the process to show two triangles are equal
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sprao534:
how to say SF=QE if SQ is parallel to EF
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