pqrs is a square . if po = 4.5cm find pr and qs
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We have a square PQRS in which two diagonals PR and QS intersect each other at O
And area of ∆POQ = 4 cm2
We know Area of PQRS = Area of ∆POQ + Area of ∆POS + Area of ∆ROS + Area of ∆ROQ
Since every square is a parallelogram and in every parallelogram, diagonals divide it into 4 triangles of equal areas, so
Area of ∆POQ = Area of ∆POS = Area of ∆ROS = Area of ∆ROQ
And we know Area of ∆POQ = 4 cm2
So,
Area of ∆POQ = Area of ∆POS = Area of ∆ROS = Area of ∆ROQ = 4 cm2
Then Area of PQRS = 4 + 4 + 4 + 4 = 16 cm2 (Ans)
We have a square PQRS in which two diagonals PR and QS intersect each other at O
And area of ∆POQ = 4 cm2
We know Area of PQRS = Area of ∆POQ + Area of ∆POS + Area of ∆ROS + Area of ∆ROQ
Since every square is a parallelogram and in every parallelogram, diagonals divide it into 4 triangles of equal areas, so
Area of ∆POQ = Area of ∆POS = Area of ∆ROS = Area of ∆ROQ
And we know Area of ∆POQ = 4 cm2
So,
Area of ∆POQ = Area of ∆POS = Area of ∆ROS = Area of ∆ROQ = 4 cm2
Then Area of PQRS = 4 + 4 + 4 + 4 = 16 cm2 (Ans)
diyashah78:
mathd
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Po=4.5cm So,Po=or=oq=os=4.5cm Because, diagonals of square bisects each other. By using Pythagoras theorem, we get the side 6.36cm or 6.4cm. So,pr=qs=6.4cm
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