Math, asked by manishranjan72, 10 months ago

pqrs is a square.if pq=8x-12 and qr=5x+18,find the length of each side of the square​

Answers

Answered by pulipatikaushik
23

Answer:10

Step-by-step explanation:

pq=8x-12 and qr=5x+18

we know in square all sides are equal in length so pq=qr ps=rs

so

8x-12=5x+18

8x-5x=18+12

3x=30

x=30/3

x=10

Answered by erinna
10

The length of each side of the square​ is 68 units.

Step-by-step explanation:

Given information: pqrs is a square, pq=8x-12 and qr=5x+18.

We know that each side of a square are congruent.

pq\cong qr

pq=qr

Substitute pq=8x-12 and qr=5x+18.

8x-12=5x+18

Isolate variable term on left side.

8x-5x=12+18

3x=30

Divide both sides by 3.

x=10

pq=8(10)-12=80-12=68

Therefore, the length of each side of the square​ is 68 units.

#Learn more

In square pqrs pq=5x+3cm qr=8x-5cm find the value of x.

https://brainly.in/question/12421254

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