PQRS is a square land of side 28m. Two semicircle grass covered portions are to be made on two of its opposite sides as shown in the figure. How much area will be left uncovered?
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Answers
Answered by
6
Lenght of side of square=28m
Area of the square=(side)^2 sq. unit
=(28^2)m^2
=784m^2
Since lenght of side of square is 28m
Diameter of the semicircles=28m
Radius of the semicircles=14m
Area of a semicircle=1/2*pi*r*r sq. unit
Area of both the semicircles=(2*1/2*pi*r*r)sq. unit
=pi*r*r sw. unit
=22/7×14×14 m^2
=616 m^2
After covering left area=(784-616) m^2
=168 m^2
Area of the square=(side)^2 sq. unit
=(28^2)m^2
=784m^2
Since lenght of side of square is 28m
Diameter of the semicircles=28m
Radius of the semicircles=14m
Area of a semicircle=1/2*pi*r*r sq. unit
Area of both the semicircles=(2*1/2*pi*r*r)sq. unit
=pi*r*r sw. unit
=22/7×14×14 m^2
=616 m^2
After covering left area=(784-616) m^2
=168 m^2
Answered by
224
Answer:
Step-by-step explanation:
Solution :-
In Square PQRS, side a = 28 m.
In two semi-circles,
PQ and RS are diameters.
So, PQ = RS = 28 m
r = 28/2 = 14 m
Area of uncovered portion = Area of square PQRS - 2 × Area of semi-circles.
Area of uncovered portion = a² - 2 × πr²/2
Area of uncovered portion = 28² - 22/7 × 14 × 14
Area of uncovered portion = 274 - 616
Area of uncovered portion = 168 m²
Hence, 168 m² area will be left uncovered.
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