PQRS is a trapezium as shown in the figure such that PQ parallel SR andSP perpendicular PQ .find the area of trapezium PQRS PQ=15cm, SQ =17mand SR=11m.
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As we see, here are a trapezium named PQRS
Parallel sides are 15cm and 15cm
Non-Parallel sides are 17m and 17m
Height is 11m
Firstly, we will change the unit metre into centimetre.
As, 1m = 100cm
So, 17m = 17×100 = 1700cm (SQ)
11m = 11×100 = 1100cm (SR)
Area of trapezium = 1/2× (b1+b2) × h
= 1/2×(15+17) × 11
= 1/2× 32× 11
= 176cm^2
Parallel sides are 15cm and 15cm
Non-Parallel sides are 17m and 17m
Height is 11m
Firstly, we will change the unit metre into centimetre.
As, 1m = 100cm
So, 17m = 17×100 = 1700cm (SQ)
11m = 11×100 = 1100cm (SR)
Area of trapezium = 1/2× (b1+b2) × h
= 1/2×(15+17) × 11
= 1/2× 32× 11
= 176cm^2
Answered by
0
Answer:
answer is 104 m²
Step-by-step explanation:
using Pythagorean theorem
h² = p²+b²
p² = h²- b²
sp = √(SQ)² - (PQ)²
sp = √(17)² - (15)²
sp = √289 - 225
sp = √64
sp = 8
area of trapezium = 1/2*(sum of parallel side )* height
= 1/2*(11+15)*8
= 26*4
= 104m²
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